Asked by sam
If 60% of a first order reaction was completed in 60 minutes, 50% of the same reaction would be completed in approximately
Answers
Answered by
DrBob222
ln(No/N) = kt
Solve for k using 100 for No and 40 for N(i.e., if it was 60% completed and you started with 100, you would have 40 left.
Then ln(No/N) = kt again, use k from above and solve for t.
Solve for k using 100 for No and 40 for N(i.e., if it was 60% completed and you started with 100, you would have 40 left.
Then ln(No/N) = kt again, use k from above and solve for t.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.