Asked by anonymous
If air is 20% oxygen, and the reaction is
2C2H2 + 5O2 --> 4CO2 + 2H2O,
What volume of oxygen would be needed to completely burn 1.00 L of acetylene (C2H2)?
I got 2.50 L but I'm not sure it's right.
What volume of air would be needed to completely burn 1.00 L of acetylene gas?
I got 3.00 L.
What volume of air would be needed to burn 1.00 L of vaporized octane?
The reaction is:
2C8H18 + 25O2 --> 16CO2 + 18H2O
I got 15.0 L.
2C2H2 + 5O2 --> 4CO2 + 2H2O,
What volume of oxygen would be needed to completely burn 1.00 L of acetylene (C2H2)?
I got 2.50 L but I'm not sure it's right.
What volume of air would be needed to completely burn 1.00 L of acetylene gas?
I got 3.00 L.
What volume of air would be needed to burn 1.00 L of vaporized octane?
The reaction is:
2C8H18 + 25O2 --> 16CO2 + 18H2O
I got 15.0 L.
Answers
Answered by
DrBob222
2.5L is right for a.
I don't agree with 3.00 L for b. What you want is ?Lair x 0.2 oxygen = 2.5 L oxygen.
?Lair = 2.5 Loxygen/0.2 oxygen = ? which I think is 12.5 L air. Check it.
12.5 L air x 0.2 oxygen = 2.5 L oxygen.
Do c the same way.
I don't agree with 3.00 L for b. What you want is ?Lair x 0.2 oxygen = 2.5 L oxygen.
?Lair = 2.5 Loxygen/0.2 oxygen = ? which I think is 12.5 L air. Check it.
12.5 L air x 0.2 oxygen = 2.5 L oxygen.
Do c the same way.
Answered by
Anonymous
I'm not exactly sure how you do the first step.
Are you using the 2.5 L from a?
So would the answer to c be 62.5 L?
? L O2 = 1.00 L x 1 mol/22.4 L x 25 mol O2/2 mol C8H18 x 22.4 L/1 mol O2
= 12.5 L O2
?L air = 12.5 L (5)
=62.5 L air
Are you using the 2.5 L from a?
So would the answer to c be 62.5 L?
? L O2 = 1.00 L x 1 mol/22.4 L x 25 mol O2/2 mol C8H18 x 22.4 L/1 mol O2
= 12.5 L O2
?L air = 12.5 L (5)
=62.5 L air
Answered by
Anonymous
okay thank you!
12.5 is correct
12.5 is correct
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.