Asked by Anonymous
                Balance the redox reaction of eq.     
Cu2S + SO4(-2) gives CuO + SO2 (Acidic )
            
        Cu2S + SO4(-2) gives CuO + SO2 (Acidic )
Answers
                    Answered by
            DrBob222
            
    First step.
Cu2S ==> 2CuO
Cu changes from total of +2 on the left to total of +4 on the right.
S changes from +6 in SO4^2- to +4 in SO2.
Now you balance the two half reactions.
    
Cu2S ==> 2CuO
Cu changes from total of +2 on the left to total of +4 on the right.
S changes from +6 in SO4^2- to +4 in SO2.
Now you balance the two half reactions.
                    Answered by
            krishna
            
    3 Cu2S + 8 SO4{-}2 + 8 H{+} = 6 CuO + 11 SO2 + 4 H2O
    
                    Answered by
            BRIJESH
            
    3Cu2s+8So4{-}+8H{+}=6Cuo+11So2+4H2o
    
                    Answered by
            Smit
            
    2Cu2S + SO4^2- + 2H2O = 4CuO + 5SO2 + 4H+
    
                    Answered by
            Smit
            
    2Cu2S + 3SO4^2- + 2H2O = 4CuO + 5SO2 + 4H+
    
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