Asked by Anonymous
Balance the redox reaction of eq.
Cu2S + SO4(-2) gives CuO + SO2 (Acidic )
Cu2S + SO4(-2) gives CuO + SO2 (Acidic )
Answers
Answered by
DrBob222
First step.
Cu2S ==> 2CuO
Cu changes from total of +2 on the left to total of +4 on the right.
S changes from +6 in SO4^2- to +4 in SO2.
Now you balance the two half reactions.
Cu2S ==> 2CuO
Cu changes from total of +2 on the left to total of +4 on the right.
S changes from +6 in SO4^2- to +4 in SO2.
Now you balance the two half reactions.
Answered by
krishna
3 Cu2S + 8 SO4{-}2 + 8 H{+} = 6 CuO + 11 SO2 + 4 H2O
Answered by
BRIJESH
3Cu2s+8So4{-}+8H{+}=6Cuo+11So2+4H2o
Answered by
Smit
2Cu2S + SO4^2- + 2H2O = 4CuO + 5SO2 + 4H+
Answered by
Smit
2Cu2S + 3SO4^2- + 2H2O = 4CuO + 5SO2 + 4H+
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