Asked by Anonymous

Balance the redox reaction of eq.
Cu2S + SO4(-2) gives CuO + SO2 (Acidic )
Answered by DrBob222
First step.
Cu2S ==> 2CuO
Cu changes from total of +2 on the left to total of +4 on the right.
S changes from +6 in SO4^2- to +4 in SO2.
Now you balance the two half reactions.
Answered by krishna
3 Cu2S + 8 SO4{-}2 + 8 H{+} = 6 CuO + 11 SO2 + 4 H2O
Answered by BRIJESH
3Cu2s+8So4{-}+8H{+}=6Cuo+11So2+4H2o
Answered by Smit
2Cu2S + SO4^2- + 2H2O = 4CuO + 5SO2 + 4H+
Answered by Smit
2Cu2S + 3SO4^2- + 2H2O = 4CuO + 5SO2 + 4H+