Asked by LOLA
balance the redox reaction
NO2^- + Ag^+ = NO3^- + Ag
NO2^- + Ag^+ = NO3^- + Ag
Answers
Answered by
DrBob222
Ag^+ + e ==> Ag
H2O+ NO2^- ==> NO3^- + 2e + 2H^+
Multiply equation 1 by 2 and equation 2 by 1 then add the two for the complete equation.
H2O+ NO2^- ==> NO3^- + 2e + 2H^+
Multiply equation 1 by 2 and equation 2 by 1 then add the two for the complete equation.
Answered by
LOLA
wouldnt h2o be on the other side because you orignally have 2h20 on the products and one h20 in the reactants so cancelling them out would make one h20 on the products side
Answered by
LOLA
sorry this is in basic solution
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