Asked by LOLA
                balance the redox reaction
NO2^- + Ag^+ = NO3^- + Ag
            
            
        NO2^- + Ag^+ = NO3^- + Ag
Answers
                    Answered by
            DrBob222
            
    Ag^+ + e ==> Ag
H2O+ NO2^- ==> NO3^- + 2e + 2H^+
Multiply equation 1 by 2 and equation 2 by 1 then add the two for the complete equation.
    
H2O+ NO2^- ==> NO3^- + 2e + 2H^+
Multiply equation 1 by 2 and equation 2 by 1 then add the two for the complete equation.
                    Answered by
            LOLA
            
    wouldnt h2o be on the other side because you orignally have 2h20 on the products and one h20 in the reactants so cancelling them out would make one h20 on the products side
    
                    Answered by
            LOLA
            
    sorry this is in basic solution
    
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