Asked by Anonymous
                a cell is based on the following reaction 
Fe(s)+2Fe+3(aq) -----> 3Fe+2 (aq) E cell= 1.18 V.
Calculate the concentration of iron (II), in M, if the cell emf is 1.28 V. when [Fe^(3+)]= 0.5 M
the answer is 0.047 M
            
        Fe(s)+2Fe+3(aq) -----> 3Fe+2 (aq) E cell= 1.18 V.
Calculate the concentration of iron (II), in M, if the cell emf is 1.28 V. when [Fe^(3+)]= 0.5 M
the answer is 0.047 M
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