Asked by Farrell

How much Al is needed to react with 675
mL of 0.655M HCl solution according to the
reaction => 2Al + 6HCl→2AlCl3+ 3H2

Help your friend!
Answered by bobpursley
moles HCL=.675*.655
so you need 1/3 of that in Al
change that to grams.
Answered by Anonymous
thank you!
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