Asked by Michelle
A 10.0mL sample of H2SO4 was neutralized by 13.5mL of 1.0M KOH. What was its molarity of H2SO4? What is the normality?
Answers
Answered by
bobpursley
Normality*volume=normality*volume
Normalityacid=1*13.5/10=13.5
Molarityacid= 13.5/2
Normalityacid=1*13.5/10=13.5
Molarityacid= 13.5/2
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