Question

A 25.0-mL sample of H2SO4 is neutralized with NaOH. What is the concentration of the H2SO4
if 35.0 mL of 0.150 M NaOH are required to
completely neutralize the acid?

Answer 1

H2SO4 + 2NaOH ==> Na2SO4 + 2H2O

mols NaOH = M x L = ?
mols H2SO4 = 2x mols NaOH (look at the coefficients n the balanced equation.)_
M H2SO4 = mols H2SO4/L H2SO4

Answer 2

.105 M

Answer 3

0.180M

Answer 4

There seems to be a mistake in the given information. We can calculate the concentration of H2SO4 using the given information as follows:

NaOH and H2SO4 react in a 1:2 molar ratio. Therefore, the number of moles of H2SO4 in the given sample can be calculated as:

moles H2SO4 = 2 × moles NaOH

moles NaOH = concentration of NaOH × volume of NaOH used = 0.150 M × 35.0 mL = 0.00525 moles

moles H2SO4 = 2 × 0.00525 = 0.0105 moles

The volume of H2SO4 used is 25.0 mL = 0.0250 L

Therefore, the concentration of H2SO4 is:

concentration of H2SO4 = moles H2SO4 / volume of H2SO4 used = 0.0105 moles / 0.0250 L = 0.420 M

So, the concentration of H2SO4 is 0.420 M.