Asked by TT
String p is 3 times as long as string q. string r is 3m longer than half the total length of strings p and q. If the total length of all three strings is 54oocm what is the length of string r.
Answers
Answered by
Jai
String P is 3 times as long as string Q:
P = 3Q
String R is 3m longer than half the total length of strings P and Q:
R = (1/2)(P + 3Q) + 3
The total length of all three strings is 5400 cm:
P + Q + R = 5400
Substituting (such that everything is in terms of Q):
3Q + Q + (1/2)(3Q + 3Q) + 3 = 5400
4Q + (1/2)(6Q) + 3 = 5400
4Q + 3Q + 3 = 5400
7Q = 5400 - 3
7Q = 5397
Q = ?
After you solved for Q, get the values for P and R by substituting the value of Q to the equations we solved above.
Hope this helps~ `u`
P = 3Q
String R is 3m longer than half the total length of strings P and Q:
R = (1/2)(P + 3Q) + 3
The total length of all three strings is 5400 cm:
P + Q + R = 5400
Substituting (such that everything is in terms of Q):
3Q + Q + (1/2)(3Q + 3Q) + 3 = 5400
4Q + (1/2)(6Q) + 3 = 5400
4Q + 3Q + 3 = 5400
7Q = 5400 - 3
7Q = 5397
Q = ?
After you solved for Q, get the values for P and R by substituting the value of Q to the equations we solved above.
Hope this helps~ `u`
Answered by
Anonymous
wrong
Answered by
Kai
1. String P is 3 times as long as string Q
so P=3Q
2. String R is 3m longer than half the total length of strings P and Q
so R=300+(3Q+Q)(1/2), or R=300+2Q
3. P+Q+R=5400
4. so solving for Q, 3Q+Q+2Q+300=5400
6. 6Q+300=5400
7. 6Q=5400-300
8. 6Q=5100
9. Q=850
10. P=850x3=2,550
11. R=((2,550+850)(1/2))+300=2,000
12. 850+2,550+2,000=5,400
so P=3Q
2. String R is 3m longer than half the total length of strings P and Q
so R=300+(3Q+Q)(1/2), or R=300+2Q
3. P+Q+R=5400
4. so solving for Q, 3Q+Q+2Q+300=5400
6. 6Q+300=5400
7. 6Q=5400-300
8. 6Q=5100
9. Q=850
10. P=850x3=2,550
11. R=((2,550+850)(1/2))+300=2,000
12. 850+2,550+2,000=5,400
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