Question
a string 0.5 m long is used to whirl a 1 kg stone in a horiziontal circle at a uniform velocity of 5m/s what is the tension on the string?
Answers
the tension in the string provides the force for the centripetal acceleration of the stone
f = m * v^2 / r = 1 * 5^2 / .5
the force is in Newtons
f = m * v^2 / r = 1 * 5^2 / .5
the force is in Newtons
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