Asked by Anonymous
Solve the equation for the given domain.
4cos^2 θ = 1 for 0 to 360 degrees.
I get 60, 120, 240, and 300. Are these correct? If so, how would I represent them with some sort of expression?
4cos^2 θ = 1 for 0 to 360 degrees.
I get 60, 120, 240, and 300. Are these correct? If so, how would I represent them with some sort of expression?
Answers
Answered by
Reiny
Your 4 solutions are correct for the primary domain
suppose we add the next 4, and we have
60, 120, 240, 300, 420, 480, 600, 660
notice that the 1st, the 3rd, the 5th, and the 7th, are obtained by adding consecutive multiples of 180°to 60°
and the 2nd, 4th, 6th, and 8th, are obtained by adding multiples of 180 to 120°
so a general solution would be:
60° + 180k , 120° + 180k° , where k is an integer.
suppose we add the next 4, and we have
60, 120, 240, 300, 420, 480, 600, 660
notice that the 1st, the 3rd, the 5th, and the 7th, are obtained by adding consecutive multiples of 180°to 60°
and the 2nd, 4th, 6th, and 8th, are obtained by adding multiples of 180 to 120°
so a general solution would be:
60° + 180k , 120° + 180k° , where k is an integer.
Answered by
Anonymous
Thank you very much!
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