Asked by TayB
The velocity function (in meters per second) is given for a particle moving along a line.
v(t) = t^2 − 2t − 15, 1 ≤ t ≤ 7
(a) Find the displacement.
(b) Find the distance traveled by the particle during the given time interval.
v(t) = t^2 − 2t − 15, 1 ≤ t ≤ 7
(a) Find the displacement.
(b) Find the distance traveled by the particle during the given time interval.
Answers
Answered by
Jai
Check you other posts, the questions are related.
Derivative of displacement (wrt time) is velocity.
Thus, integral of velocity is displacement.
D(t) = ∫(t^2 − 2t − 15) dt
D(t) = ?
After you solved for the integration, evaluate this from time t=1 to t=7.
Derivative of displacement (wrt time) is velocity.
Thus, integral of velocity is displacement.
D(t) = ∫(t^2 − 2t − 15) dt
D(t) = ?
After you solved for the integration, evaluate this from time t=1 to t=7.
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