The reaction N2(g)+3H2(g)<-->2NH3(g) begins with 1.15 M N2 and 1.36 M H2. At equilibrium the concentration of NH3 is 0.78 M.
Determine the extent of reaction.
4 answers
I don't know what you mean by extent of reaction.
I think it is the percent yield. the answer is 86.029411764706 but i'm not sure how
.......N2 + 3H2 ==> 2NH3
I.....1.15..1.36......0
C......-x....-3x.....2x
E....1.15-x..1.36-3x..2x
So if 2x = 0.78 then x = 0.39
The way they get 86.02% is this.
(3x)/1.36]*100 = 86.029 but that makes no sense to me.
I Googled "extent of reaction" and came up with several sites. Here is one such site.
http://en.wikipedia.org/wiki/Extent_of_reaction
I tried that with no luck.
I.....1.15..1.36......0
C......-x....-3x.....2x
E....1.15-x..1.36-3x..2x
So if 2x = 0.78 then x = 0.39
The way they get 86.02% is this.
(3x)/1.36]*100 = 86.029 but that makes no sense to me.
I Googled "extent of reaction" and came up with several sites. Here is one such site.
http://en.wikipedia.org/wiki/Extent_of_reaction
I tried that with no luck.
hmm ok thanks though!
1 answer