Asked by darian
A firework is launched into the air from ground level with an initial velocity of 128 ft/s. If acceleration due to gravity is –16 ft/s2, what is the maximum height reached by the firework?
Answers
Answered by
Steve
recall that the height h is given by
h(t) = 128t - 16t^2
That's just your good old friend, the parabola. Find its vertex -- that is the maximum height.
h(t) = 128t - 16t^2
That's just your good old friend, the parabola. Find its vertex -- that is the maximum height.
Answered by
khihnoehfv9 dsn
256ft
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