Ask a New Question

Question

A firework is launched at the rate of 10 feet per second from a point on the ground 50 feet from an observer. To 2 decimal places in radians per second, find the rate of change of the angle of elevation when the firework is 40 feet above the ground. Type your answer in the space below. If your answer is a number less than 1, place a leading "0" before the decimal point (ex: 0.35).
10 years ago

Answers

Steve
at height h,

tanθ = h/50

sec^2θ dθ/dt = 1/50

so, plug in your numbers and evaluate dθ/dt
10 years ago

Related Questions

A 9.3 kg firework is launched straight up and at its maximum height 45 m it explodes into three part... what is a factor firework A firework rocket is launched vertically from rest and loses 60% of its mass during a burn time of 4... A firework is launched into the air from ground level with an initial velocity of 128 ft/s. If accel... A firework is launched from a cliff overlooking the ocean. The elevation of the firework shell, in f... A firework whose mass is 7kg is launched vertically up into the air. After it reaches its the height... A firework is set off from the roof of a building. Its height, h, above the ground in feet after t s... Firework have. Energy Do you want a third firework decide whether you want to watch it from the ground or from the roof of... When set off a certain firework follows the path of the quadratic function h = -25/36x^2 + 16 2/3x,...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use