Question

Iron -59 has a half -life of 45.1 days. How old is an iron nail if the Fe-59 content is 25% that of a new sample of iron? Show all calculations leading to a solution.

Answer 1

First determine the constant, k, for the reaction.
k = 0.693/t_1/2

Then ln(No/N) = kt
Let No be 100 (but you may use any number you want as long as N is 25% of No.
Then N = 25
k from above.
Solve for t in days.

Answer 2

Anyone help me through the steps, please?

Answer 3

If you want more help the only thing we can do is to work the problem and present it to you on a platter. And whatever it is that you don't understand gets put off until another day. I have an alternative. Why not explain what you don't understand. The steps are there. There is no chemistry involved. It's all just a little arithmetic. Have you thought of plugging those numbers into the equation and seeing what happens?

Answer 4

Would please work the problem with me? Thanks!

Answer 5

Is Dr. Bob saying
No/N=Kt
After finding the constant (1.38?)=k

100/25=1.38t
4=1.38t
2.89=t ????
That's what I got and it doesn't seem right to me.