Asked by George
10.0 g of H2SO4 are added to 50. 0 mL of water.
Is the answer 200. If not how do you approach the problem to get the solution.
Is the answer 200. If not how do you approach the problem to get the solution.
Answers
Answered by
GK
<b>The answer to what question is 200? </b>
•If the question is to find the % by mass, then
(50.0mL)(1.00g/mL) = 50.0g H2O, and
mass% = (100)[10.0g / (10.0g + 50.0g)] = 16.67%
•If the question is to find the grams/liter, then
[(10.0g)/(50.0mL)](1000mL/L) = 200 g/L
•If the question is to find the # of moles / L, then divide the previous answer by the molar mass of H2SO4.
•If the question is to find the % by mass, then
(50.0mL)(1.00g/mL) = 50.0g H2O, and
mass% = (100)[10.0g / (10.0g + 50.0g)] = 16.67%
•If the question is to find the grams/liter, then
[(10.0g)/(50.0mL)](1000mL/L) = 200 g/L
•If the question is to find the # of moles / L, then divide the previous answer by the molar mass of H2SO4.
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