Asked by raeg
A rain cloud contains 3.56 x 107 kg of water vapor. How long would it take (in seconds) for a 4.5 kW pump to raise the same amount of water to the cloud which has an altitude of 1741.4 meters?
Answers
Answered by
Henry
4.5kW = 4500 W. = 4500 J./s
Work = F*d = Mg * d = 3.56*10^7 * 1741.4
= 6199.4*10^7 = 6.199*10^10 J.
T = 6.2*10^10J. * 1s/4500J = 1.38*10^7 s
= 833.3 Hours.
Work = F*d = Mg * d = 3.56*10^7 * 1741.4
= 6199.4*10^7 = 6.199*10^10 J.
T = 6.2*10^10J. * 1s/4500J = 1.38*10^7 s
= 833.3 Hours.
Answered by
dhon joe
Dear Henry, you forgot gravity in your work calculation
you got the mass and the height, but not gravity....
so you are off by a lot
the answer will be many years, not less than one year...
you got the mass and the height, but not gravity....
so you are off by a lot
the answer will be many years, not less than one year...
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