Asked by jessi
A certain sum of money was shared among 3 friends, A, B, and C. A received 3/7 of the money, and B got 2/3 as much as A. C received $49 less than A.
a) Find the ratio of B’s money to C’s money.
b) How much money did C receive?
a) Find the ratio of B’s money to C’s money.
b) How much money did C receive?
Answers
Answered by
Reiny
let the total be x
A got (3/7)x = 3x/7
B got (2/3)(3x/7) = 6x/21 = 2x/7
C got 3x/7 - 49
3x/7 + 2x/7+ 3x/7 - 49 = x
times 7
3x + 2x + 3x - 343 = 7x
x = 343
A has 147
B has 98
C has 98
ratio of B:C = 1:1
A got (3/7)x = 3x/7
B got (2/3)(3x/7) = 6x/21 = 2x/7
C got 3x/7 - 49
3x/7 + 2x/7+ 3x/7 - 49 = x
times 7
3x + 2x + 3x - 343 = 7x
x = 343
A has 147
B has 98
C has 98
ratio of B:C = 1:1
Answered by
sarah
After spending 80% of her money Lei has 100.00 left...How much was her money before?
Answered by
Gabija
184
Answered by
daedae
180
Answered by
The dumb one
Idk I am "muy stupido"
Answered by
Anonymous
Isabella has $20 she spent $5 for lunch and $10 for dinner
Answered by
Antwone
I don't understand
Answered by
Anonymous
I don't understand. Four girls shared a certain sum of money. The first received 1/6, the second 1/4 and the third 1/2 of it. If the fourth received $5 how much was the sum shared
Answered by
Reiny
It is 65
Sorry
Sorry
Answered by
.
65 for what?
Answered by
Maya see
Three girls DEVI,RASH and NIC shared a sum of money in the ratio 6:5:4
calculate RASH 's share
please write the answer
and its explanation
calculate RASH 's share
please write the answer
and its explanation
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