Use the info below to calculate how much it would cost you to produce 500g of NiSO4*6H2O . don't forget to include the cost of the original nickel token .
Na2CO3*H2O costs $6.58/3 kg
6 M H2SO4 costs $12.65/5L
9 M HNO3 costs $10.53/2.5L
Show clearly how you obtained your answer. NiSO4*6H2O sells at $21.70 for 500g . If you could sell 500g of your NiSO4*6H2O for $21.70 what profit would you make?
Here's my data to be used:
Mass of nickel token- 4.49g
Mass of Na2CO3*H2O- 22.50g
Volume of 6 M H2SO4 used- 20ml
Mass of NiSO4*6H2O formed- 12.52g
This is the last question of my lab so please help !!
3 answers
Do you have the equation(s)? Can you use stoichiometry to calculate the grams NiSO4.6H2O you can produce? Exactly what trouble are you having with this?
I have no idea how to do this like idk I'm really confused with this question..
You must have something in your experiment from which you can get the equations. I can guess what you might do but that isn't good enough. I presume you add Ni to HNO3 to dissolve the metal BUT you're not given any grams HNO3 used. Where does the Na2CO3 come in? What comes after that?
0 answers