Asked by Maya

Use the info below to calculate how much it would cost you to produce 500g of NiSO4*6H2O . don't forget to include the cost of the original nickel token .

Na2CO3*H2O costs $6.58/3 kg
6 M H2SO4 costs $12.65/5L
9 M HNO3 costs $10.53/2.5L
Show clearly how you obtained your answer. NiSO4*6H2O sells at $21.70 for 500g . If you could sell 500g of your NiSO4*6H2O for $21.70 what profit would you make?

Here's my data to be used:
Mass of nickel token- 4.49g
Mass of Na2CO3*H2O- 22.50g
Volume of 6 M H2SO4 used- 20ml
Mass of NiSO4*6H2O formed- 12.52g


This is the last question of my lab so please help !!
Answered by DrBob222
Do you have the equation(s)? Can you use stoichiometry to calculate the grams NiSO4.6H2O you can produce? Exactly what trouble are you having with this?
Answered by Maya
I have no idea how to do this like idk I'm really confused with this question..
Answered by DrBob222
You must have something in your experiment from which you can get the equations. I can guess what you might do but that isn't good enough. I presume you add Ni to HNO3 to dissolve the metal BUT you're not given any grams HNO3 used. Where does the Na2CO3 come in? What comes after that?
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