Asked by jewel
given the following info for water molar heat of fusion 6.02kj/mol calculate the total quanity of heat evolved when 10.0g of steam is condensed,cooled,and frozen to ice at -50 degrees
Answers
Answered by
DrBob222
q1 = heat released when steam vapor @ 100 C is condensed to liquid water @ 100 C.
q1 = mass steam x heat vaporization
q2 = heat released in cooling liquid water from 100 C to zero C.
q2 = mass water x specific heat water x (Tfinal-Tinitial).
q3 = heat released changing liquid water at zero C to ice at zero C.
q3 = mass water x heat fusion
q4 = heat released in cooling ice from zero C to ice at -50 C.
q4 = mass ice x specific heat ice x (Tfinal-Tinitial)
Total Q = q1 + q2 + q3 + q4.
q1 = mass steam x heat vaporization
q2 = heat released in cooling liquid water from 100 C to zero C.
q2 = mass water x specific heat water x (Tfinal-Tinitial).
q3 = heat released changing liquid water at zero C to ice at zero C.
q3 = mass water x heat fusion
q4 = heat released in cooling ice from zero C to ice at -50 C.
q4 = mass ice x specific heat ice x (Tfinal-Tinitial)
Total Q = q1 + q2 + q3 + q4.
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