Ask a New Question

Question

Prove (sin4x)/(1-cos4x) = cotx - 1/2(cscxsecx)

Please help me get started on this question... I'm at a lost as for what to do first....
10 years ago

Answers

Steve
sin4x/(1-cos4x)
(2 sin2x cos2x)/(2sin^2 2x)
cos2x/sin2x
(2cos^2 x - 1)/(2sinx cosx)
cosx/sinx - 1/(2sinx cosx)
cotx - 1/2 cscx secx
10 years ago

Related Questions

cos4x^2 + sin4x^2? Prove cos4x = 8 cos^4x-8 cos^2x+1 cos4x*cos3x + sin4x*sin3x simplify (cos4x-cos2x)/(sin4x+sin2x) the answer choices are : cotx, tanx, cotxtanx, or 1 prove that (cotx+tanx)(cotx-tanx) = 1/(sin^2 x) - 1/(cos^x) Prove cotx-1/cotx+1=1-sin2x/cos2x Prove cotx-1/cotx+1 = sec2x - tan2x I prove till cotx-1/cotx+1 =1/1+tanx - tanx/1+tanx Prove that if y = cotx then dy/dx = - (cscx)^2. Hint: cotx = cosx/sinx prove that sin^4x-cos^4x/cotx= tanx-2cosxsinx Prove the identity Cos⁴x + sin²x = sin⁴x + cos²x
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use