Asked by Steffi
Let’s say you have a bedroom drawer that contains about 2 red socks, 4 white socks, and 8 blue socks. Without looking in the drawer, you pick out a sock, take it back, and then pick out a second sock. What could the probability be if the first sock is white and the second sock is blue? Write the final answer is a/b.
P(first sock is white and second sock is blue)=
(My answer is 6/49) is that right?
P(first sock is white and second sock is blue)=
(My answer is 6/49) is that right?
Answers
Answered by
Reiny
No
Prob(first is white) = 4/14 = 2/7
now there are only 13 socks left, so
prob(2nd is blue) = 8/13
prob(1st white, then blue) = (2/7)(8/13) = 16/91
Prob(first is white) = 4/14 = 2/7
now there are only 13 socks left, so
prob(2nd is blue) = 8/13
prob(1st white, then blue) = (2/7)(8/13) = 16/91
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