From the given information, we deduce that
It takes 4.184 J/g * 1000 g = 4184 J to raise the temperature of 1 L of water by 1°C.
Assuming that all 1000J of heat are absorbed by the 1 L of water, then by proportion, the temperature increase equals 0.239°C.
1°C * (1000/4184)
A liter of water is used to cool some electronics. If 1000 J of heat is given off by the electronics, by what
temperature does the water increase? One liter of water has a mass of 1 kg and a specific heat of 4.184 J/(g
°C).
I can not get this..please help
1 answer
1 answer