Question
Solve each equation for 0<_ 0<_ 2pi(3.14)
E) 18sin^2(0) + 3cos0 -17 =0
E) 18sin^2(0) + 3cos0 -17 =0
Answers
Steve
18sin^2x + 3cosx - 17 0
18 - 18cos^2x + 3cosx - 17 = 0
18cos^2x - 3cosx - 1 = 0
(6cosx-1)(3cosx+1) = 0
cosx = 1/6 or cosx = -1/3
x = 1.40 or 2π-1.40
x = π-1.23 or π+1.23
18 - 18cos^2x + 3cosx - 17 = 0
18cos^2x - 3cosx - 1 = 0
(6cosx-1)(3cosx+1) = 0
cosx = 1/6 or cosx = -1/3
x = 1.40 or 2π-1.40
x = π-1.23 or π+1.23