Asked by Mike
Need some direction.. where do I start?
Vinegar is a 5% (mass/mass) solution of acetic acid in water. If vinegar has a density of 1.06 g/mL, what is the concentration in molar?
Vinegar is a 5% (mass/mass) solution of acetic acid in water. If vinegar has a density of 1.06 g/mL, what is the concentration in molar?
Answers
Answered by
bobpursley
Molarity=moles/liter
Now from the density, since you know water has a density of 1.00, then .06g/ml must be acetic acid. In a liter, then, 60grams/liter
Molarity=60g/liter*MolmassAceticAcid
= 60g/60.05g/mole= 1Molar
Now from the density, since you know water has a density of 1.00, then .06g/ml must be acetic acid. In a liter, then, 60grams/liter
Molarity=60g/liter*MolmassAceticAcid
= 60g/60.05g/mole= 1Molar
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