Asked by Mahendra Nath Pandey
A solid of R.D. 4.2, is found to weigh 0.200kgf in air
Find its apparent weight in water
Find its apparent weight in water
Answers
Answered by
bobpursley
If the relative density is 4.2 compared to water, then in water it will weigh the same amount less the weight of the water displaced.
Example:
if the volume is 1m^3, with RD 4.2, then its weight is 4200N. In water, its apparent weigh is 4200N-1m^3*1E3kg*9.8= 4200-980=3400N
I wonder if you are learning kgf as force, instead of using the SI unit of Newtons.
Example:
if the volume is 1m^3, with RD 4.2, then its weight is 4200N. In water, its apparent weigh is 4200N-1m^3*1E3kg*9.8= 4200-980=3400N
I wonder if you are learning kgf as force, instead of using the SI unit of Newtons.
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