Asked by BUB
                Find the width of the rectangle.
-----------------------
= Perimeter=30 in. =
= = W=Width
===============
L=Length
P=w and l=11
p=2l+2w
30=(2x11)+2w
30=22+2w (Think:if 2 x w=8, then w=___divided____
w=8
So the width is 8 inches.
I don't know what the w=_____ divided _____ is
            
        -----------------------
= Perimeter=30 in. =
= = W=Width
===============
L=Length
P=w and l=11
p=2l+2w
30=(2x11)+2w
30=22+2w (Think:if 2 x w=8, then w=___divided____
w=8
So the width is 8 inches.
I don't know what the w=_____ divided _____ is
Answers
                    Answered by
            Jai
            
    No it's not 8. But you're almost correct, you just forgot to divide it by 2. :)
From your solution,
p = 2l + 2w
30 = (2 * 11) + 2w
30 = 22 + 2w
Put the 22 (from the right side of equation) to the left side, but by doing so, you must change its sign to its opposite. It's originally positive, so it will become negative on the other side:
30 + (-22) = 2w
30 - 22 = 2w
8 = 2w
To get w alone, divide everything by 2:
8/2 = 2w/2
4 = w
w = 4 inches
hope this helps~ `u`
    
From your solution,
p = 2l + 2w
30 = (2 * 11) + 2w
30 = 22 + 2w
Put the 22 (from the right side of equation) to the left side, but by doing so, you must change its sign to its opposite. It's originally positive, so it will become negative on the other side:
30 + (-22) = 2w
30 - 22 = 2w
8 = 2w
To get w alone, divide everything by 2:
8/2 = 2w/2
4 = w
w = 4 inches
hope this helps~ `u`
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