Asked by BUB
Find the width of the rectangle.
-----------------------
= Perimeter=30 in. =
= = W=Width
===============
L=Length
P=w and l=11
p=2l+2w
30=(2x11)+2w
30=22+2w (Think:if 2 x w=8, then w=___divided____
w=8
So the width is 8 inches.
I don't know what the w=_____ divided _____ is
-----------------------
= Perimeter=30 in. =
= = W=Width
===============
L=Length
P=w and l=11
p=2l+2w
30=(2x11)+2w
30=22+2w (Think:if 2 x w=8, then w=___divided____
w=8
So the width is 8 inches.
I don't know what the w=_____ divided _____ is
Answers
Answered by
Jai
No it's not 8. But you're almost correct, you just forgot to divide it by 2. :)
From your solution,
p = 2l + 2w
30 = (2 * 11) + 2w
30 = 22 + 2w
Put the 22 (from the right side of equation) to the left side, but by doing so, you must change its sign to its opposite. It's originally positive, so it will become negative on the other side:
30 + (-22) = 2w
30 - 22 = 2w
8 = 2w
To get w alone, divide everything by 2:
8/2 = 2w/2
4 = w
w = 4 inches
hope this helps~ `u`
From your solution,
p = 2l + 2w
30 = (2 * 11) + 2w
30 = 22 + 2w
Put the 22 (from the right side of equation) to the left side, but by doing so, you must change its sign to its opposite. It's originally positive, so it will become negative on the other side:
30 + (-22) = 2w
30 - 22 = 2w
8 = 2w
To get w alone, divide everything by 2:
8/2 = 2w/2
4 = w
w = 4 inches
hope this helps~ `u`
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