Asked by Shane
Let 70.0 J of heat be added to a particular ideal gas. As a result, its volume changes from 65.0 cm3 to 169.0 cm3 while the pressure remains constant at 1.7 atm. By how much did the internal energy of the gas change?
Answers
Answered by
bobpursley
P*deltaV= external work -work internal
1.7atm*104cm^3=-work done internally+70J
101.3E3*1.7*104E-6 J-70J=-work done internally
work internal=-.1013*1.7*104*6+70J
= -17.9+70=52.1 J
check that.
1.7atm*104cm^3=-work done internally+70J
101.3E3*1.7*104E-6 J-70J=-work done internally
work internal=-.1013*1.7*104*6+70J
= -17.9+70=52.1 J
check that.
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