Asked by Shane
                Let 70.0 J of heat be added to a particular ideal gas. As a result, its volume changes from 65.0 cm3 to 169.0 cm3 while the pressure remains constant at 1.7 atm. By how much did the internal energy of the gas change? 
            
            
        Answers
                    Answered by
            bobpursley
            
    P*deltaV= external work -work internal
1.7atm*104cm^3=-work done internally+70J
101.3E3*1.7*104E-6 J-70J=-work done internally
work internal=-.1013*1.7*104*6+70J
= -17.9+70=52.1 J
check that.
    
1.7atm*104cm^3=-work done internally+70J
101.3E3*1.7*104E-6 J-70J=-work done internally
work internal=-.1013*1.7*104*6+70J
= -17.9+70=52.1 J
check that.
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.