Asked by Sora

Write each series in summation notation:
*this is the only one that i cant solve

-2+4+(-6)+8+(-10)+12
Please help! :(

Answers

Answered by Reiny
Had they all been positive, then it would be
∑ (2n) from n=1 to 6
but they alternate + - , so you need a multiplier that flip-flops between ±
how about (-1)^n, if n is odd you get a negative, if n = even you get a positive, so ....

∑ (2n)(-1)^n from n=1 to 6
Answered by Sora
Thanksssss
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