The general term of the given series can be written in the form of an^2 + bn + c,
where a = 1, b = 0, and c = 0 for the first term (1*3^2),
a = 2, b = 0, and c = 0 for the second term (2*4^2),
a = 3, b = 0, and c = 0 for the third term (3*5^2).
So, the given series can be expressed in summation notation as:
Σ(n=1 to n) [n(n+2)^2]
where Σ represents the sum, n=1 is the starting point, and n is the number of terms.
I hope this helps!
Express the series in summation notation where the sums are to n terms. 1*3^2+2*4^2+3*5^2
2 answers
how about,
n
∑ k(k+2)^2
k=1
n
∑ k(k+2)^2
k=1