Asked by Karly
How much heat is required to convert solid ice with a mass of 875 g and at a temperature of -11.5 °C to liquid water at a temperature of 52.0 °C? (The specific heat of ice is cice = 2100 J/kgK, the specific heat of water is cwater = 4186.8 J/kgK, and the heat of fusion for water is: Lf = 334 kJ/kg.)
I did -> (.875)(2100)(325-261.5) = 116681J
then (.875)(334000)= 292250J
then added those two answers together and got 408931J and it keeps saying that is wrong..
I did -> (.875)(2100)(325-261.5) = 116681J
then (.875)(334000)= 292250J
then added those two answers together and got 408931J and it keeps saying that is wrong..
Answers
Answered by
bobpursley
It is wrong.
figure
a. heat to heat ice to 0C from -11.5
Note: there is no reason to conver to K. One kelvin change is exactly one C change.
Then heat to melt the ice at 0C
then to heat the water from 0 C to 52 C
add them up.
figure
a. heat to heat ice to 0C from -11.5
Note: there is no reason to conver to K. One kelvin change is exactly one C change.
Then heat to melt the ice at 0C
then to heat the water from 0 C to 52 C
add them up.
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