Asked by Anonymous
How much heat is required to vaporize 343g of liquid ethanol at its boiling point?
ΔHvap+38.6 Kj\mol
ΔHvap+38.6 Kj\mol
Answers
Answered by
DrBob222
q = mass x deltaHvap. Watch the units, you must change either 343 g to moles or change delta H vap to kJ/g
Answered by
Colton DarWIN
You are STUPID!
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.