Asked by Anonymous

How much heat is required to vaporize 343g of liquid ethanol at its boiling point?

ΔHvap+38.6 Kj\mol

Answers

Answered by DrBob222
q = mass x deltaHvap. Watch the units, you must change either 343 g to moles or change delta H vap to kJ/g
Answered by Colton DarWIN
You are STUPID!
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