Asked by Sara
                What is the distance between the parallel lines having equations 2x+2y=16 and x+y=0?
I'm getting 2 as my answer but the answer is supposed to be 4√2
            
        I'm getting 2 as my answer but the answer is supposed to be 4√2
Answers
                    Answered by
            Damon
            
    find slope of perpendicular
original is slope = -1
so slope of perpendicular is
-1/-1 = 1
pick a point on line 2, like (0,0)
then equation of perpendicular through that point is
y = x (just to make it east)
where does y = x hit the first line?
2 x + 2 x = 16
x = 4
then y = 4
so
distance form(0,0) to (4,4)
sqrt (4^2 + 4^2 ) = sqrt (2*16)
= 4 sqrt 2
    
original is slope = -1
so slope of perpendicular is
-1/-1 = 1
pick a point on line 2, like (0,0)
then equation of perpendicular through that point is
y = x (just to make it east)
where does y = x hit the first line?
2 x + 2 x = 16
x = 4
then y = 4
so
distance form(0,0) to (4,4)
sqrt (4^2 + 4^2 ) = sqrt (2*16)
= 4 sqrt 2
                    Answered by
            Ryan kustin
            
    Hey, Damon, can you please look at my reply on my problem?
    
                    Answered by
            Damon
            
    Beats me Ryan
    
                    Answered by
            Sara
            
    thanks!
    
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