Asked by Anonymous
In a titration, 4.1 g of an acid (HX) requires
32.8 mL of 0.74 M NaOH(aq) for complete
reaction. What is the molar mass of the acid?
Answer in units of g/mol.
32.8 mL of 0.74 M NaOH(aq) for complete
reaction. What is the molar mass of the acid?
Answer in units of g/mol.
Answers
Answered by
DrBob222
.........HX + NaOH ==> NaX + H2O
mols NaOH taken = M x L = ?
mols HX = mols NaOH since 1 mol HX = 1 mol NaOH in the balanced equation.
Then mols HX = grams HX/molar mass HX. You know grams and mols, solve for molar mass.
mols NaOH taken = M x L = ?
mols HX = mols NaOH since 1 mol HX = 1 mol NaOH in the balanced equation.
Then mols HX = grams HX/molar mass HX. You know grams and mols, solve for molar mass.
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