Asked by Nora
A photoelectric experiment is performed by separately shining a laser of 450 nm
(blue light) and 560 nm (yellow light) on a metal surface and measuring the
number and kinetic energy of the ejected electrons.
The threshold frequency of
the metal is 6.00•10^14 Hz.
a. Compare the number of electrons ejected from the metal for each of the
lasers when directed at the metal for the same amount of time. Explain
How do you find the number of electrons from all of this? I only know how to solve for wavelength and energy??
(blue light) and 560 nm (yellow light) on a metal surface and measuring the
number and kinetic energy of the ejected electrons.
The threshold frequency of
the metal is 6.00•10^14 Hz.
a. Compare the number of electrons ejected from the metal for each of the
lasers when directed at the metal for the same amount of time. Explain
How do you find the number of electrons from all of this? I only know how to solve for wavelength and energy??
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