Asked by Jackie
How would you fine the relative extrema of
f(x)=x+8^-x ?
I know the first step is to find the derivative, which when I did I got
f'(x)=1+[(-1)(ln(8))(8^-x)]
Did I find the derivative correctly? And if I did, how do I find the zeroes of that??
f(x)=x+8^-x ?
I know the first step is to find the derivative, which when I did I got
f'(x)=1+[(-1)(ln(8))(8^-x)]
Did I find the derivative correctly? And if I did, how do I find the zeroes of that??
Answers
Answered by
Jackie
Would I end up having to take the log of both sides, and end up with zeroes at x=.35207?
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