Asked by Anonymous
a chemist puts 50g of chemical a in beaker 1 and 25 g of chemical b in beaker 2 she places bot beaker into a larger container. as the chemicals evaporated the gas react into a white solid what mass of solid will form if chemicals react
Answers
Answered by
DrBob222
Frankly, I don't think this question can be answered and be confident the answer is correct. Beaker a COULD be HCl or NH3 and beaker b COULD be NH3 or HCl. And of course they might be thousands of other elements/compounds. And since you don't know what chemical is in which beaker you have no way of know how much of anything is formed. My experience tells me the solid PROBABLY is NH4Cl.
If beaker a is NH3 and beaker b is HCl, you have 50/17 = 2.94 mols NH3 and 25/35.5 = 0.7 mols HCl. Under those circumstance you would have about 38 g NH4Cl formed with HCl as the limiting reagent. However, if beaker a is HCl and beaker b is NH3, you will have 50/35.5 = 1.4 mols HCl and 25/17 = 1.5 mols NH3 and this will form abut 75 g NH4Cl with HCl as the limiting reagent.
So it could be either of those amounts and it could be compound x and neither of those numbers. I don't know who thought up this exercise but I think it's a waste of your time and our time.
If beaker a is NH3 and beaker b is HCl, you have 50/17 = 2.94 mols NH3 and 25/35.5 = 0.7 mols HCl. Under those circumstance you would have about 38 g NH4Cl formed with HCl as the limiting reagent. However, if beaker a is HCl and beaker b is NH3, you will have 50/35.5 = 1.4 mols HCl and 25/17 = 1.5 mols NH3 and this will form abut 75 g NH4Cl with HCl as the limiting reagent.
So it could be either of those amounts and it could be compound x and neither of those numbers. I don't know who thought up this exercise but I think it's a waste of your time and our time.
Answered by
BbroisBBQ
AHH TO MUCH SCIENCE
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