An industrial chemist puts 1.00 mol each of H2(g) and CO2(g) in a 1.00-L container at 800oC. When equilibrium is established, 0.49 mol of CO(g) is in the container. Find Kc at 800 C for the following reaction:

Question

An industrial chemist puts 1.00 mol each of H2(g) and CO2(g) in a 1.00-L container at 800oC.  When equilibrium is established, 0.49 mol of CO(g) is in the container.  Find Kc at 800 C for the following reaction: 
H2(g) + CO2(g) ⇌ H2O(g) + CO(g).

bobpursley · Answer

H2 + CO2 <> H2O + C0 all gases. K= [H2O][CO]/[H2}{CO2] K= (.49)^2 /(1-.49)(1-.49)=(.49/.51)^2 check my work