Asked by allexelle
What are the real or imaginary solution of the polynomials x^4 -52x^2 +576=0
Answers
Answered by
Anonymous
let u^2=x^4, so you have now
u^2-52u+576=0
(u-26)^2=0
u= 26
x^2=26
u= +- sqrt 26
check that
u^2-52u+576=0
(u-26)^2=0
u= 26
x^2=26
u= +- sqrt 26
check that
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