Asked by alex

what are the real and imaginary zeros of the equation 2x^3 + 5x^2 - 3x + 7

Answers

Answered by Steve
I find no rational zeros, but the real zero is very near -1.3, so

f(x) = (x+1.3)(2x^2+6.4x-6.12)

I assume you have some graphical or numeric tools for solving general polynomials.
Answered by Steve
oops - the real root is at -3.282
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