Question
A Hammer weighing 3kg strikes the head of a nail with a speed of 2m/s and drives it by 1cm into the wall. find the impulse?
Answers
Impulse = M*V = 3 * 2 = 6
1cm = 0.01m
0.01m= 1/2(10.0)t
t= 0.01m/2.0m s^-1
= 0.002s
Accelaration = -10.0m/s/0.002s
= -5000m/s^2
0.01m= 1/2(10.0)t
t= 0.01m/2.0m s^-1
= 0.002s
Accelaration = -10.0m/s/0.002s
= -5000m/s^2
A hammer weighing 3kg strikes the head of A nail with a speed of 2mper sec drives by 1cm into the wall the impulse imparted to the wall is
Impulse =change in momentum
=M(v-u)
=3kg (0-2m/s)
=-6kg m/s
=M(v-u)
=3kg (0-2m/s)
=-6kg m/s
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