Asked by Anonymous

A hammer with 10 J of kinetic energy hits a nail and pushes it 5.0 mm into a plank.
Both the hammer and nail come to rest after the collision.
What is the average force that acts on the nail while it moves the 5.0 mm?
Answered by Elena
KE=mv²/2
v²= 2•KE/m
a= v²/2s
F=ma=mv²/2s= 2m•KE/2s m=
= KE/s=10/0.005 =2000 N
Answered by l,mpkml
74161
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