Question
What volume (mL) of the solvent benzene should be added to 142 mL of the solute CH3CN to generate a solution that is 2.68% by mass CH3CN?
Answers
You don't have enough information. You need the density of benzene, the density of CH3CN, and the density of the solution.
Here is the other information..
Molar Mass (g/mol)
CH3CN 41.05
C6H6 78.12
Density (kg/m3):
CH3CN 785.7
C6H6 878.6
Name/Formula:
acetonitrile
CH3CN
benzene
C6H6
Molar Mass (g/mol)
CH3CN 41.05
C6H6 78.12
Density (kg/m3):
CH3CN 785.7
C6H6 878.6
Name/Formula:
acetonitrile
CH3CN
benzene
C6H6
I assume this is mass/mass percent.
142 mL CH3CN has what mass? mass=vol x density or mass CH3CN = 142 mL x 0.7857 g/mL = 111.569 grams CH3CN.
What mass solution must we have to equal 2.68%? [111.569 g/mass solution]*100 = 2.68% and solve for g solution. g soln = 299.002 g solution. How much of that is CH3CN and how much benzene.
Total mass = 299.002 g
mass CH3CN = 111.569 g
difference = ??g = mass benzene.
volume benzene = mass benzene/density vol benzene = ?? g benzene/0.8786. I would then round the answer to 3 significant figures.
Post your work if you get stuck. Check my thinking. Check my work.
142 mL CH3CN has what mass? mass=vol x density or mass CH3CN = 142 mL x 0.7857 g/mL = 111.569 grams CH3CN.
What mass solution must we have to equal 2.68%? [111.569 g/mass solution]*100 = 2.68% and solve for g solution. g soln = 299.002 g solution. How much of that is CH3CN and how much benzene.
Total mass = 299.002 g
mass CH3CN = 111.569 g
difference = ??g = mass benzene.
volume benzene = mass benzene/density vol benzene = ?? g benzene/0.8786. I would then round the answer to 3 significant figures.
Post your work if you get stuck. Check my thinking. Check my work.
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