Asked by Emily
Consider a solution made by mixing 100 mL of 2.0 M acetic acid (Ka= 1.8e-5) with 100 mL of 0.00020 M benzoic acid
(Ka= 6.4e-5). How many moles of solid NaOH must be added to the solution so that
half of the benzoic acid is protonated (i.e. such that [HA] = [A-] for benzoic acid)?
(Ka= 6.4e-5). How many moles of solid NaOH must be added to the solution so that
half of the benzoic acid is protonated (i.e. such that [HA] = [A-] for benzoic acid)?
Answers
Answered by
DrBob222
I would add mols NaOH to neutralize all of the acetic acid and add enough to neutralize 1/2 benzoic acid.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.