Question

1. The sum of the ages of two brothers is 46. The younger brother is 10 more than a third of the older brother's age. How old is the younger brother?

2. You have 59 total coins for a total of $12.05. You only have quarters and dimes. How many of each coin do you have?

Answer 1

y = 10 + x/3
y + x = 46 so y = 46 - x

46 - x = 10 + x/3

36 = 4 x/3
x = 27
y = 46-27 = 19
========================
25 q + 10 d = 1205
d = 59 - q
so
25 q + 590 - 10 q = 1205
etc