Asked by Anonymous
A colony of Salmonella bacteria
has a current population of 1000
organisms. If this particular strain has
a doubling time, d, of 18 minutes,
calculate the future population after
180 minutes.
1000er^18
1e+54
has a current population of 1000
organisms. If this particular strain has
a doubling time, d, of 18 minutes,
calculate the future population after
180 minutes.
1000er^18
1e+54
Answers
Answered by
Damon
It doubles ten times
t x
0 1000
18 2000 one time
36 4000 2 times
54 8000 3 times
72 16000 4 times or 1000*2^4
90
108
......
180 1024*1000 = 1,024,000 = 1000*2^10
t x
0 1000
18 2000 one time
36 4000 2 times
54 8000 3 times
72 16000 4 times or 1000*2^4
90
108
......
180 1024*1000 = 1,024,000 = 1000*2^10
Answered by
Reiny
You might want the equation:
number = 1000 (2^(t/18) )
so when t = 180
number = 1000 (2^10) = 1000(2^10) , the same result that Damon got
number = 1000 (2^(t/18) )
so when t = 180
number = 1000 (2^10) = 1000(2^10) , the same result that Damon got
Answered by
Anonymous
1024000?
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