Asked by Marissa
At 20 degrees celcius the vapor pressure of toluene is 22 mmhg and that of benzene is 75 mmhg. Assume an ideal solution, equimolar in benzene and toluene. At 20 degrees celcius what is the mole fraction of benzene in the vapor in equilibrium with this solution?
If you use pv=nRt how would you find v and n. Or how do you solve this a different way
If you use pv=nRt how would you find v and n. Or how do you solve this a different way
Answers
Answered by
DrBob222
Note the correct spelling of celsius.
Equimolar means Xtol = Xben = 0.5
ptol = Xtol*Po toluene.
pben = Xben*P. benzene.
Ptotal = ptol + pben
Xtol vapor = ptol vapor/Ptotal
Xben vapor = pben vapor/Ptotal
Equimolar means Xtol = Xben = 0.5
ptol = Xtol*Po toluene.
pben = Xben*P. benzene.
Ptotal = ptol + pben
Xtol vapor = ptol vapor/Ptotal
Xben vapor = pben vapor/Ptotal
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