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1. An electrical circuit consists of a battery with 2 cells,each with an EMF of 12 volts and an internal resistance of of 0.4 ohms,connected in parallel. An ammeter with an internal resistance of 0.15 ohms is connected in series with resistor Ra=2ohms and Rb=4ohms

Calculate the following

A. The total internal resistance of the battery.
B. The ammeter reading

1 answer

A. Ri = 0.4 + 0.4 = 0.8 Ohms

B. I = E/(Ri+Rm+Ra+Rb) = 24/6.95 = 3.45A
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