Asked by Kat
an object falls from a 3m height what is the speed of the object just before it touches the ground?
Answers
Answered by
Jai
The object experiences uniformly accelerated motion (UAM) so we can use the formula:
vf^2 - vo^2 = 2gd
where
vf = final velocity
vo = initial velocity
g = acceleration due to gravity = 9.8 m/s^2
d = distance
Since the object is in free fall, vo is zero:
vf^2 - 0 = 2*9.8*3
vf^2 = 58.8
vf = 7.67 m/s
hope this helps~ `u`
vf^2 - vo^2 = 2gd
where
vf = final velocity
vo = initial velocity
g = acceleration due to gravity = 9.8 m/s^2
d = distance
Since the object is in free fall, vo is zero:
vf^2 - 0 = 2*9.8*3
vf^2 = 58.8
vf = 7.67 m/s
hope this helps~ `u`
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